((9*(x^2))+1)*0,32=1

Solution for ((9*(x^2))+1)*0,32=1 equation:

((9(x^2))+1)*0.32=1

We move all terms to the left:

((9(x^2))+1)*0.32-(1)=0

determiningTheFunctionDomain
(9x^2+1)*0.32-1=0

We multiply parentheses

2.88x^2+0.32-1=0

We add all the numbers together, and all the variables

2.88x^2-0.68=0

a = 2.88; b = 0; c = -0.68;
Δ = b2-4ac
Δ = 02-4·2.88·(-0.68)
Δ = 7.8336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{7.8336}}{2*2.88}=\frac{0-\sqrt{7.8336}}{5.76}
=-\frac{\sqrt{}}{5.76}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{7.8336}}{2*2.88}=\frac{0+\sqrt{7.8336}}{5.76}
=\frac{\sqrt{}}{5.76}
$